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Kamila [148]
3 years ago
15

One solution to the problem below is 2. what is the other solution c^2-4=0

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

c^2-4=0\qquad|+4\\\\c^2=4\to c=\pm\sqrt4\\\\c=-2\ \vee\ c=2

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=> D2 (D2 - 5D + 6) - (D2 - 5D + 6) = 0

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Now

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