First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
Safdsfghjklphuiyotrdtufchvjbkn;pp;lrsyketdgxvcb nmklj;pu8yutiyfgch bmhjkityfjhvyfug . =235678
Order (B) 5 × 6 of the matrix can be multiplied by matrix a to create matrix ab.
<h3>
What is a matrix?</h3>
- A matrix is a rectangular array or table of numbers, symbols, or expressions that are organized in rows and columns to represent a mathematical object or an attribute of such an object in mathematics.
- For instance, consider a matrix with two rows and three columns.
To find the order of matrix:
- We must first check the dimension of two matrices, say matrix A by matrix B, before we may multiply them.
- Multiplication is achievable if the number of columns in the first matrix, A, equals the number of rows in the second matrix.
- Dimension is assigned to the provided matrix: 6 × 5
- This means the given matrix contains six rows and five columns.
- As a result, the second matrix MUST have 5 rows in order for multiplication to be POSSIBLE.
- The only matrix with 5 rows among the above alternatives is the matrix with dimension (B) 5 × 6.
To prove:
- In other words, the inner products of the dimensions should be equal.
- That is; (a × b)(b × a) is possible but (a ×b)(c × b) is impossible.
- The dimensions of the matrix are given by, row × column.
Therefore, order (B) 5 × 6 of the matrix can be multiplied by matrix a to create matrix ab.
Know more about matrix here:
brainly.com/question/24079385
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I cannot see the images, but...
y = | x | + 5
consider the absolute value function. You know that for every value of x, y will be greater than or equal to 5. this means that the y-intercept will also be the bottom of the curve.
Plug a few values in for an idea of what the graph will look like:
f(-1) = 6 (-1,6)
f(1) = 6 (1, 6)
f(-2) = 7 (-2, 7)
f(2) = 7 (2, 7)
The graph will have a minimum value at (0,5), where two lines will converge. The graph will look like a pointy cone with its point at (0,5), with two lines pointing outward and upward from this point. Confirm that the graph passes through the coordinates provided above!
Answer:
is this an essay question?