If someone refers to a coordinate as 125' West, they are referring to a

How do the finch population change over the course of one year

yan [13]

The population had a short increase, then a more sustained decrease. it has to do to their beak depths.

8 0

4 years ago

Why are an forest an important resource?

algol [13]

Answer:

Forests are a valuable resource providing food, shelter, wildlife habitat, fuel, and daily supplies such as medicinal ingredients and paper. Forests play an important role in balancing the Earth's CO2 supply and exchange, acting as a key link between the atmosphere, geosphere, and hydrosphere.

8 0

3 years ago

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Which statements describe the Richter scale? Check all that apply.

Kazeer [188]

<h3>ANSWER:</h3>

A. It gauges fault movement during an earthquake.

D. It increases in magnitude as the amount of damage increases.

E. It determines an earthquake’s magnitude based on the size of its seismic waves.

<h3>EXPLANATION:</h3>

The Richter magnitude scale determines the magnitude that is the size of the earthquake. It can measure earthquakes even of 4.5 or above all over the world through the use of seismograph where seismic waves interprets the magnitude of earthquake. A Richter number of less than 2.0 is not felt by people whereas Richter number of 8.0 to 9.9 show massive destruction. Hence the magnitude of increases of Richter scale when damage is increased.

8 0

4 years ago

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Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is: