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Aloiza [94]
3 years ago
9

Write an algebraic expression to model the given context.Give your answer in simplest form. (please explain)

Mathematics
2 answers:
Tatiana [17]3 years ago
7 0
P(100-15)/100

p(85)/100

0.85p
musickatia [10]3 years ago
3 0

Answer:

The required expression is 0.85p.

Step-by-step explanation:

Consider the provided information.

Let the original price is p.

Now it is given that we need to write an expression that the original price p of an item less a 15% discount.

15% of p can be written as:

\frac{15}{100}\times p

0.15\times p

0.15p

The original price p of an item less a 15% discount.

This can be written as:

p-0.15p = 0.85p

Hence, the required expression is 0.85p.

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Given ZW=20. Answer the questions please. ​
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a) Corresponding angles of similar figures are congruent, so \angle B \cong \boxed{\angle Z}

b) Scale factor = (image)/(preimage). Since we are looking for ABCD to WZYX, this means that WZYX is the image and ABCD is the preimage. Thus, the scale factor is \frac{25}{10}=\boxed{5/2}

c) Since the scale factor is 5/2,

\frac{20}{t}=\frac{5}[2}\\\\40=5t\\ \\ t=\boxed{8}

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2 years ago
What is the trigonometric ratio for sin Z ?
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3 years ago
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Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

4 0
4 years ago
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