Just 13 a and b please and thank you
1 answer:
You might be interested in
Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where
is the final velocity in a direction after the acceleration is applied,
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
- <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then:
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction:
Best way to convert measurements in the standard measurement system is to use the phrase "King Henry Died By Drinking Chocalote Milk"
K- Kilo
H- Hecto
D- Deca
B- Base (meter, liter, gram)
D- Deci
C- Centi
M- Milli
If you go up from the B, you move the decimal left, if you go down from the B, you move the decimal that many times to the right.
The picture will probably help explain better.
3) 10,640 g
5) idk which it needs to be converted to
7) 3,700 mg
K- Kilo
H- Hecto
D- Deca
B- Base (meter, liter, gram)
D- Deci
C- Centi
M- Milli
If you go up from the B, you move the decimal left, if you go down from the B, you move the decimal that many times to the right.
The picture will probably help explain better.
3) 10,640 g
5) idk which it needs to be converted to
7) 3,700 mg