Answer:
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Step-by-step explanation:
Answer:
We readily separate the variables and integrate:
∫dP/P=∫(k+bcos2
t)dt
ln P=kt+(b/2)*sin2t+ln C
Clearly C = Po, so we find that P(t) = Poexp(kt + (b/2)* sin 2t). The 271- curve with the typical numerical values P_o = 100, k = 0.03, and b = 0.06. It oscillates about the curve which represents natural growth with P_o and k = 0.03. We see that the two agree at the end of each full year.
note:
find the attached graph
p=qx+4x−5 would be the answer to your problem. Math Papa is a good website to use for alegebra or math
Answer:
<u>You have:</u>
- 9 weeks ⇒ 116 assignments ⇔ 116/9 ≈ 13 a week
- 9*5= 45 days ⇒ 116 assignments ⇔ 116/45 ≈ 2.6 a day
- 2.25 months ⇒ 116 assignments ⇔ 116/2.25 ≈ 52 a month
<u>If you consider working weekends as well:</u>
- 9*7 = 63 days ⇒ 116 assignments ⇔ 116/63 ≈ 2 a day
