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Cerrena [4.2K]
3 years ago
12

The original price P of a shirt less $5 discount​

Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0

Answer:

p-5

Step-by-step explanation:

Fudgin [204]3 years ago
3 0

Answer:

P - 5

Step-by-step explanation:

hello

original price is P

$5 discount means that the final price is P - 5

hope this helps

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What is the solution to the system of equations?
Artist 52 [7]

Answer:

No solutions .........

Step-by-step explanation:

3x-4y=7

-12x+16y=10

Multiply 1st equation by 4, you get:

12x-16y=28

Add the 1st and 3rd equations:

0x+0y=38

0(x+y)=38

(x+y)=38/0 which is undefined

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2 years ago
Solve for m<br> (- 11/6) + m = -2/9<br> ​
joja [24]

Answer:

m= -29/18

Step-by-step explanation:

3 0
2 years ago
Evaluate <br> 9C5<br> and <br> 11P4<br> .
Lelechka [254]
9C5=\dfrac{9!}{5!4!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=6\cdot7\cdot3=126\\\\&#10;11P4=\dfrac{11!}{7!}=8\cdot9\cdot10\cdot11=7920
7 0
3 years ago
The admission fee to an amusement park is $28. It costs an additional p dollars to rent a locker to hold your belongings. The to
Nezavi [6.7K]

it costs 8 dollars to rent a locker because

28x5=140

180-140=40

40/5= 8

6 0
2 years ago
he radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had lost
elena-s [515]

Answer:

The bones were 12,485 years old at the time they were​ discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element​ carbon-14 has a​ half-life of 5750 years.

This means that A(5750) = 0.5A(0), and we use this to find k. So

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-5750k}

e^{-5750k} = 0.5

\ln{e^{-5750k}} = \ln{0.5}

-5750k = \ln{0.5}

k = -\frac{\ln{0.5}}{5750}

k = 0.00012054733

So

A(t) = A(0)e^{-0.00012054733t}

A scientist determined that the bones from a mastodon had lost 77.8 ​% of their​ carbon-14. How old were the bones at the time they were​ discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

A(t) = 0.222A(0)

Then

0.222A(0) = A(0)e^{-0.00012054733t}

e^{-0.00012054733t} = 0.222

\ln{e^{-0.00012054733t}} = \ln{0.222}

-0.00012054733t = \ln{0.222}

t = -\frac{\ln{0.222}}{0.00012054733}

t = 12485

The bones were 12,485 years old at the time they were​ discovered.

8 0
3 years ago
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