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Svetradugi [14.3K]
3 years ago
7

Solve and simplify: x(x - 1) = 121 – x​

Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0

Answer:

\boxed{\bold{x  \ =  \ 11  \ or  \ x  \ =  \ -11}}

Explanation:

\bold{x(x  \ -  \ 1)  \ =  \ 121  \ -  \ x}

Simplify both sides of the equation

x² − x = −x + 121

Add x to both sides

x² − x + x = −x + 121 + x

x² = 121

Take square root

x = ± √121

x = 11 or x = −11

GuDViN [60]3 years ago
3 0

Answer:

x=11

Step-by-step explanation:

x(x-1)=121-x\\\\x^2-x=121-x\\\\x^2=121\\\\x=\sqrt{121}\\\\x=11

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What is 12 to 44 simlified
elena-s [515]

\frac{12}{44} simplified is \frac{3}{11}

I got this by dividing both the numerator and denominator by 4

Hope this helps

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7 0
3 years ago
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Q/19 &lt; 4<br><br> pls be correct if you type it !!!!
babymother [125]

Answer:

q<76

Step-by-step explanation:

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3 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
Please anyone help me The measure of an angle is five times the measure of its supplementary angle. What is the measure of each
Radda [10]

Answer:

150 and 30

Step-by-step explanation:

Hello!

Supplementary angles are angles that when added up equal 180

Which can be shown by

x + x = 180

Since one has to be 5 times bigger we put a 5 in front of one of the x's

5x + x = 180

5x is an angle and x is the other

Now we solve for x

5x + x = 180

Combine like terms

6x = 180

Divide by 6

x = 30

Now we put that into each angle

5(30) = 150

30

The answer is 150 and 30

Hope this Helps!

5 0
3 years ago
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Help me plz idk this at all
worty [1.4K]

Step-by-step explanation:

sin theta = opp / hyp

sin theta × hyp = opp

sin60 × 30 = opp

.866 × 30 = opp

25.98° = opp

*Theta is the 0 with a line through it

8 0
3 years ago
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