The calculated distance of this throw is given as 41.23 meters.
<h3>How to solve for the distance of the throw.</h3>
In order to solve for this, we have to make use of the formula for calculating distance.
This is given as:
This is substituted as
sqr(50-10)²+(5-15)²
= √40² +√ -10²
= √1700
= 41.23
b. The points were created to find the distance by making use of yards from the goals and the yards from the sidelines.
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Answer:
x = 10
Step-by-step explanation:
The line from the vertex to the base is a perpendicular bisector.
Consider the left side right triangle, eith base = x
Using Pythagoras' identity.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
( x )² + 7² = ( )², that is
x² + 49 = 74 ( subtract 49 from both sides )
x² = 25 ( multiply both sides by 4 to clear the fraction )
x² = 100 ( take the square root of both sides )
x = = 10
Answer:
y-4=-3/4(x+5)
Step-by-step explanation:
y-y1=m(x-x1)
y-4=-3/4(x-(-5))
y-4=-3/4(x+5)
Answer:
Increases then decreases
Step-by-step explanation:
A Baseball after being hit is the most common example