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Stella [2.4K]
4 years ago
14

How do you solve 3/x^2+5x+6 + x-1/x+2= 7/x+3

Mathematics
1 answer:
gulaghasi [49]4 years ago
8 0

Answer:

it equal 69 is a arat with 24 legs and 5+5=30

Step-by-step explanation:

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Solve the equation <br><br> 3(x+2) = 2(2 - x)
RideAnS [48]

Answer:

x=-2/5

Step-by-step explanation:


6 0
3 years ago
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Help, I need it fast! D:
patriot [66]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish the simple interest formula which we will require to solve this problem as displayed below:

Simple Interest = Principal × Rate of Interest × No. of Time Periods

I = PRN

Now let's substitute the values from the problem into this formula as displayed below:

I = $90

P = ?

R = 6%

N = 3 years

I = PRN

90 = P × 0.06 × 3

P = 90 / 0.06 × 3

P = 90 / 0.18

P = $500

ANSWER:

As the principal and the amount borrowed is the same, Claire borrowed $500. Therefore, the answer is:

D ) $500

Please mark as brainliest if you found this helpful! :)
Thank you <3
5 0
3 years ago
(6^2)^4 ÷ 6^18<br><br> please help brainliest
Vedmedyk [2.9K]

Answer:

1/60466176

Step-by-step explanation:

Given: (6^2)^4 ÷ 6^18

Parentheses: 36^4 ÷ 6^18

36^4 ÷ 36^9 (Because 6^18=6^2^9=36^9)

36^-5 (Exponents get subtracted)

1/(36^5)

1/60466176

Another way:

(6^2)^4 ÷ 6^18

6^(2*4) ÷ 6^18

6^8 ÷ 6^18

6^(8-18)

6^-10

1/(6^10)

1/60466176

7 0
4 years ago
BRAINLIEST FOR RIGHT ANSWERS!
exis [7]

Answer:

The formula for finding volume of a cone is (in this case),

V=(3.14)(r^2)(h/3)

With this formula in mind, you would simply substitute in.

V=(3.14)(2^2)(9/3)

You could work that out for yourself on your own, but to save you the time, it is 37.68 in. cubed.

Step-by-step explanation:

hope i helped

6 0
3 years ago
Read 2 more answers
Joelle wants to place an oversized image which is 30.51 cm wide so that it appears centered on the page. The width of the page i
Naya [18.7K]

-4.46cm

Step-by-step explanation:

The horizontal midpoint of the page is;

The horizontal midpoint of the image is given as;

For the image to be centered, these to midpoints must be on the same point in the axis.

If we take the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795cm.  The distance that goes beyond this leftmost edge is computed as;

On the axis, this is on the negative side. Therefore, the horizontal position for the left edge of the image that Joelle should use to center the image is -4.46cm.

3 0
3 years ago
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