Which expressions form an equation with the given expression?

Mathematics

1 answer:

kolezko [41]2 years ago

8 0

Numbers 2, 4 and 5 are the correct answers.
Hope this helps!

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Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

2 years ago

Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1

taurus [48]

$\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.$