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3 years ago

1 Pete owed each of his three sisters $10. Which statement accurately represents how much Pete owes in total?

Mathematics

1 answer:

Kaylis [27]3 years ago

5 0

Answer:

$30 in total.

Step-by-step explanation:

Since he owes 3 people 10 dollars each, you simply need to multiply:

10×3= $30 dollars in total.

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A circle is shown. Secants E G and D G intersect at point G outside of the circle. Secant E G intersects the circle at point F a

USPshnik [31]

Answer:

Step-by-step explanation:

The formula we need here is

$6(6+x)=5(5+x+3)$

which simplifies to

$6(6+x)=5(8+x)$

which simplifies to

36 + 6x = 40 + 5x and

x = 4

So DG = 5 + 4 + 3 which is 12

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3 years ago

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N76 [4]

Answer:

c. 15in

Step-by-step explanation:

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2 years ago

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Solve for b b+4.22=7.08

mr Goodwill [35]

Steps to solve:

b + 4.22 = 7.08

~Subtract 4.22 to both sides

b = 2.86

Best of Luck!

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3 years ago

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BRAINLIEST + POINTS! Help needed and explanation please!

sattari [20]

The Median is the middle value.

Arrange the numbers in order from smallest to largest:

Seattle: 23.78 , 32.46, 40.30, 45.79, 49.42, 55.14

Since there is an even number, the median is found by adding the 2 middle numbers and dividing by 2.

Median for Seattle: 40.30 + 45.79 = 86.09 / 2 = 43.045

Now do the same for Las Vegas:

2.33, 3.72, 3.84, 4.11, 5.62, 8.79

Median for Las Vegas: 3.84 + 4.11 = 7.95 / 2 = 3.975

Difference: 43.045 - 3.975 = 39.07

The answer is B.

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3 years ago

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When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v squared w

Sati [7]

Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

$\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}$

This first-order differential equation has separable variables, which are cleared herein:

$\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv$

The solution of this integral is:

$t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]$

$\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } } \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)$

$\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\right]$

$v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m} \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m} \right) }\right]$

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3 years ago