Answer:
1
Step-by-step explanation:
anything with a power of 0 is 1
Answer:
Step-by-step explanation:
trsnymuy,jumythrgegr4trgafbehtrsngyjkuymukyfyjumhfngbdfvsdsfewrgthyjukilk,jmhnbgvfvdfsergthygrnjrsthsgrthyjterefwgrehtryjumhukymjhkuyjmhkijhmkiujhmgngbfvfdbgnyhjhtgrfsdvfbgnhjythrgefvfdbg
To answer this problem, the utilization of the provided formula is of utmost importance.
The formula to be used would be for the combination with no repetition since it is what is asked and possibly happens when involving the products mentioned in the problem. The formula would be
n! where in
------------- n = number of things to choose from
(n - r)! r! r = number of things needed to form
the symbol ! is called a factorial function which replaces the sequence of multiplying a number in a descending order.
lets substitute and solve
13!
--------------
(13 - 6)! 6!
13!
-------------
(7!) 6!
6,227,020,800
-------------------
5,040 x 720
6,227,020,800
-------------------
3,628,800
1,716
The answer would be 1,716.
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Step-by-step explanation:
Firstly convert the diameter into cm
t480812.5cm³hus 3.5×100=350cm
Volume=
=480812.5cm³
