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SCORPION-xisa [38]
3 years ago
7

HELPPP!!SIMPLIFY!!!5x²-7y+3x²-8y​

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

8

x

2

−

15

y

Step-by-step explanation:

Hope that helps

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What value(s) of x will make each equation below true
Dahasolnce [82]

We need to solve for x. Let's try problem b:

2x-6=3x+1-x-7

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

2x-6=2x-6

Since this is true, your answer would be:

All real numbers

------------------------------------------------------------------

Let's solve for problem c:

3x+1=43

Let's isolate x, so subtract 1 from both sides:

3x=42

Since x can't have a coefficient, divide both sides by 3:

\frac{3x}{3}=\frac{42}{3}

x=14

So, only the value of 14 would make this equation true.

------------------------------------------------------------------

Let's try problem d:

4x-1=4x+7

Let's get our whole numbers on the right side. Add 1 to both sides:

4x=4x+8

Subtract 4x from the right side on both sides:

0=8

Since this is not true, your answer would be:

No solution

7 0
4 years ago
-0.333333333 into a fraction
sweet [91]

Answer:

-1/3

Step-by-step explanation:

1/3 is 0.33333... and then you just put a negative sign in front of it.

4 0
4 years ago
Read 2 more answers
gabrielle went to the movie theatre with her friend. she had $20.00 to spend. The movie ticket cost $6.25 . Write an inequality
svp [43]
$20.00-$6.25=?

?=13.75
3 0
4 years ago
in a certain game, a fair die is rolled and a player gains 20 points if the die shows a 6. if the die does not show a 6, the pla
BaLLatris [955]

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

  • Addition of 20 points for rolling a 6
  • Removal of 3 points for not rolling a 6

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}

\mathbf{E(x) = \frac{20}6 -  \frac{15}6}

Take LCM

\mathbf{E(x) = \frac{5}6}

\mathbf{E(x) = 0.83}

The number of games is 100.

So, the expected gain is:

\mathbf{Gain = 100 \times 0.83}

\mathbf{Gain = 83}

Hence, the expected total gain is 83 points

Read more about expected value at:

brainly.com/question/13499496

5 0
3 years ago
I need this asap! will give a thanks and brainliest to whoever answers !!
Rufina [12.5K]

Answer:

10 spiders

18 grasshoppers

7 0
3 years ago
Read 2 more answers
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