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ziro4ka [17]
3 years ago
10

Find the value of the missing coefficient in the factored form of 8f^3-216g^3

Mathematics
1 answer:
adoni [48]3 years ago
7 0

Answer:

The value of the missing coefficient is 12

Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- The factorization of the difference of two cubes like a³ - b³, is a

  product of a binomial and trinomial

- The binomial is the cube root of the first term and the second term

∵ The ∛a³ = a and ∛b³ = b

∴ The binomial is (a - b)

- We will find the trinomial from the binomial by square the 1st term

 of the binomial and multiply the 1st term and the 2nd term of the

 binomial with opposite sign of the binomial and square the 2nd

 term of the binomial

∴ The trinomial is (a² + ab + b²

∴ The factorization of (a³ - b³) is (a - b)(a² + ab + b²)

* Lets solve the problem

∵ 8f³ - 216g³ is the difference of two cubes

∵ ∛(8f³) = 2f

∵ ∛(216g³) = 6g

∴ The binomial is (2f - 6g)

- Lets make the trinomial

∵ (2f)² = 4f²

∵ (2f)(6g) = 12fg

∵ (6g)² = 36g²

∴ The trinomial = (4f² + 12fg + 36g²)

∴ The factorization of 8f³ - 216g³ = (2f - 6g)(4f² + 12fg + 36g²)

∴ The value of the missing coefficient is 12

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The sum of all digits in the numbers 44, 45, and 46 is 27 because (4+4)+(4+5)+(4+6)=27. Find the sum of digits in the first 25 c
Tom [10]

Answer:

The sum of the digits in the first 25 counting numbers, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, and 25 is 127

Step-by-step explanation:

The question regards the addition of single digits in numbers and asks of the sum of the digits in the first 25 numbers as follows;

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 0 + 1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 + 1 + 6 + 1 + 7 + 1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 + 2 + 2 + 2 + 3 + 2 + 4  + 2 + 5 = 127

The sum of the digits in the first 25 counting numbers, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, and 25 = 127.

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