6
Answer: The worm slithers 48 inches in an hour. The snail slithers 52 inches in an hour.
If we start by making both the races into equations we get 5w+4s=448 inch and 2w+3s=252 inch. If we then add both the equations together we get 7w+7s=700 inch. Then we divide it all to get 1w+1s=100 inch. Then we can subtract the second race from the first to get 3w+1s=196 inch. We now know that 2w=96 inch, and can therefor divide whit 2 to find out w=48. We can then figure out how fast the snail is moving by multiplying 48 whit w and dividing the answer by s.
7
A 3 scoops $1.28 2 scoops $.87 1.28-.87= 41 .87-.41-.41= 06. A cone costs $.06 and one scoop ice cream costs $.41
B. .06+.41•4=$1.70
8
A. Delivery is $20. One cord is $120.
B. 1 1/2 cord costs $200. ($180 for the cords and $20 for the delivery)
9
Can’t see full question.
D because 6/20 is correct and the three wrong super wrong hope it helps
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
In order of what is shown on the pic:
- Trinomial
- Monomial
- Trinomial
- Binomial
- Polynomial with four terms
Step-by-step explanation:
Again, in the same order as above:
1. The first has three terms, making it a trinomial
2. 7x^2 - 7x^2 +4x
The 7x^2 cancels out and we are left with only 4x
Since there is one value, it is a monomial
3. This one has three terms, making it a trinomial
4. This one has two terms, making it a binomial
5. The last one has four terms, making it a polynomial with four terms.
Answer:
9/4 ÷ 7/2
9/4 × 2/7
9/14
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