All categories

2 years ago

Identify the domain of the function

Mathematics

2 answers:

sertanlavr [38]2 years ago

7 0

The answer is C. is right

Roman55 [17]2 years ago

4 0

Answer:

C) (-4, 4]

Step-by-step explanation:

We have been given a graph of the function as shown in the picture. Now using that graph, we need to find the domain of the function and match with the given choices to find the correct domain.

Where given choices are :

A) [-4, 4)

B) [-4, 4]

C) (-4, 4]

D) (-4, 4)

Remember that we use ( or ) for open circle. and [ or ] for close circle.

Hence correct domain is

C) (-4, 4]

You might be interested in

Can someone help please

sertanlavr [38]

The answer is The second choice (B)

4 0

2 years ago

Hruuuuuuu? wyddd?? boi? gurl? other? idrk just ask or answer

Kruka [31]

Answer:

hi:))

Step-by-step explanation:

im greatttt hbu??? currently doing school work ugh :| my pronouns she/her or They/them

4 0

1 year ago

Read 2 more answers

£50 is worth €65 how many euros is £220 worth

Cloud [144]

Answer:

£220 is worth €247

4 0

2 years ago

Write the equation of the parabola in vertex form.

givi [52]

Answer: -9 = a(1 - 3)² + 3

Step-by-step explanation:

Vertex Form Equation:

y = a(x - h)² + k

vertex: (h, k) which means

h = 3

k = 3

because your vertex is (3, 3).

Your point is (1, -9) which is (x, y).

This means

x = 1

y = -9

Now, plug everything into your Vertex Form Equation:

-9 = a(1 - 3)² + 3

That’s your equation and final answer, but of course, if you need to, you can solve for a if you need to.

If a is positive, the parabola opens up. If a is negative, the parabola opens down.

Hope this helps!

3 0

3 years ago

What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

Komok [63]

Hi there! The answer is n = 10.

$(2 {x}^{9} {y}^{n} )(4 {x}^{2} {y}^{10} ) = 8 {x}^{11} {y}^{20}$

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
${x}^{9} \times {x}^{2} = {x}^{9 + 2} = x {}^{11}$

The powers of y work the same way.
${y}^{n} \times {y}^{10} = {y}^{n + 10} = {y}^{20}$

Hence, n = 10, since
${y}^{10 + 10} = {y}^{20}$

8 0

3 years ago