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jeka57 [31]
4 years ago
14

Write the percent 0.8 as a fraction or mixed number in simplest form

Mathematics
2 answers:
iragen [17]4 years ago
6 0
8/10 is the fraction form of .8. In percentages it would be 80%.
Nadusha1986 [10]4 years ago
4 0

Answer:

4/5

Step-by-step explanation:

0.8 = 80%

Fraction:  8/10   because the 8 is in the tenths place

Simplified fraction: 4/5   divide the 8 and 10 by 2

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Complete the point-slope equation of the line through (-4,8) and (4,4)
S_A_V [24]

Answer:

y-4= -1/2(x-4)

Step-by-step explanation:

First you have to find the slope to write it in point slope

to do this you find change in Y over change in X

From -4 to 4 is postivite 8 and from 8 to 4 its -4

Now you do -4 divided by 8 and get -0.5 or -1/2 for slope now pick one of the points and put it in the formula y-y1=m(x-x1)

3 0
3 years ago
Read 2 more answers
ANSWER FOR BRAINLIST!<br><br> has to be right answer tho
Inga [223]

Answer:

406 meters squared

Step-by-step explanation:

14 times 5= 70 (Section 1)

21 times 16= 336 (Section 2)

(Combine Sections 1 and 2)

336 + 70= 406

*I'm not 100% certain that this is correct, but I'm pretty sure it is*

6 0
4 years ago
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Complete the inequality for this graph.<br> y ≤ [?]
Eduardwww [97]

y< 3

3 is the correct answer.

8 0
3 years ago
Read 2 more answers
Please needed as soon as possible thank you
stich3 [128]

Answer:

43. = \frac{.0045}{100}

44. 4\frac{9}{10}

45. 8

Step-by-step explanation:

43. 0.45% = .0045

      = \frac{.0045}{100}

44. \frac{1}{2} • 9\frac{4}{5}

    = 4\frac{9}{10}

45. VIII = 8

3 0
3 years ago
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal
ohaa [14]

Answer: AAA similarity.


Step-by-step explanation:  CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

∠DCE ≅ ∠ACB [same angle]

Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.


8 0
3 years ago
Read 2 more answers
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