This is not possible, because if you had 11 coins, then not even 11 dimes will cover it, because 11*10 is 110, or $1.10
Applying the percentages, and considering that 70% of the first group drinks at least 2 glasses of water a day, it is found that 0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
The team is divided into two equal groups, hence, each represents 50%.
The <em>percentages </em>associated with drinking at least 2 glasses of water a day is:
- 70% of 50%(first group)
- 75% of 50%(second group)
Hence, applying the weighed percentage, the total percentage is:
0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
A similar problem is given at brainly.com/question/1517088
Answer:
The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.
Step-by-step explanation:
For a statistically rare event, its probability is relatively small and the event is very unlikely to occur. Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:
p(event) = 0.01 = 1/100
where p(event) is the probability of the event.
In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.
