All categories

3 years ago

What did the river valley civilizations have in common? What were the main differences between them?

1 answer:

4 0

There are four settled societies that each developed agriculture independently along major rivers that are traditionally considered the early river valley civilizations. The are the Mesopotamian civilizations, the Nile River civilizations, the Indus River civilizations, and the Yellow and Yangtze River civilizations.

You might be interested in

What are cultures of West and central Africa based on?

Yanka [14]

They are based on Islam or Christianity

4 0

4 years ago

How is telling time related to the geographic grid

Mariulka [41]

A method of measuring time based on time at the prime meridian/ ... Title, legend, grid system, direction, scale ... If you wanted to draw a map for the purpose of telling time, how many degrees ...

3 0

3 years ago

Which of the following describes a predation relationship?

saw5 [17]

Answer:

Sharks and seals or Sharks and orcas

Explanation:

I hope this helps :)

8 0

3 years ago

Read 2 more answers

Which problems are likely the result of urbanization

Lunna [17]

Global warming, loss of natural habitats, extinction of multiple species, etc

3 0

3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

zzz [600]

Answer:

y= -7/2x-26/2 or y= -7/2x-13

Explanation:

To solve this question you need all of these formulas:

gradient: $\frac{y2-y1}{x2-x1}$ , Point-Slope $y-y1=m(x-x1)$ ,

perpendicular m $(m1)x(m2)=-1$ , Midpoint $(\frac{x1+x2}{2}$ , $\frac{y1+y2}{2} )$

and equation of a line $y=mx+c$

where m stands for gradient

First things first.

To start you have to know the data of the line that includes the two endpoints, so you calculate its gradient (m) of this line with the gradient fromula: $m=\frac{-4-(-8)}{5-(-9)}$ , which equals 4/14 or 2/7

(It can also be called rise/run) (Remember the rule of signs where - and - equal +)

with that information you can proceed with the point-slope or point-gradient formula, so you plug the values: y-(-8) = 2/7 (x-(-9)), which results in y+8=2/7(x+9) and then y+8=2/7x+18/7.

To finish the equation you move eight to the other side. To simplify things you can change it into a fraction as I did, and remember to change signs.

y=2/7x+18/7 -8 -> y=2/7x+18/7-56/7 . This gives us the number of y=2/7x-38/7, which is the equation of the first line.

Now to know the gradient of the second line you apply the formula of perpendicular bisector where m1 x m2 = -1. We know m1 (gradient of the first line) is 2/7, so m2 = $\frac{-1}{2/7}$ = -7/2. m2 is therefore -7/2

Now you have to know the midpoint between the two endpoints, which will act as the start point of the perpendicular bisector

M (midpoint) = $(\frac{-9+5}{2} ,$ $\frac{8+(-4)}{2} )$ , which give us the coordinates of (-2, -6)

(remember, x coordinate is always first)

with this point we can apply again the point-slope formula to know the equation of the line:

y-(-6)=-7/2(x-(-2)) -> y+6=-7/2(x+2) -> y+6=-7/2x - 14/2

Move the 6 to isolate the y

y=-7/2x -14/2 - 12/2

which equals y= -7/2x -26/2

You can check the results in this page: GraphPlotter

https://www.transum.org/Maths/Activity/Graph/Desmos.asp

To make sure the answer is correct.

Hope it helps :)

8 0

2 years ago