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leva [86]
2 years ago
7

What is the equation of the line that is perpendicular to the given line and has an x-intercept of 6 ?

Mathematics
1 answer:
allochka39001 [22]2 years ago
3 0

Answer:

y = 4/3x - 8

Step-by-step explanation:

slope of given line is -3/4 so the perpendicular slope is 4/3

line goes through (6, 0)

y = mx + b

0 = 4/3(6) + b

-8 = b

y = 4/3x - 8

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X4y(4) = yx2(13), calculate (x+y)2
Delicious77 [7]

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

"X4y(4) = yx2(13)"


Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


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3 years ago
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Llana [10]

Answer:

8x²−6xy+20x−15y

Step-by-step explanation:

(4x−3y)(2x+5)

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=8x²+20x−6xy−15y

=8x²−6xy+20x−15y

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Answer:

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Answer:

Step-by-step explanation:

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