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3 years ago

1/3(4y-2)+ 1/9(6y+10)

2 answers:

6 0

Here are the steps :
1- Distributing

1/3 (4y-2) + 1/9 (6y + 10 )

1/3 ( 4y ) = 4/3 = 1 1/3 y
1/3 ( -2 ) = -2/3

1/9 ( 6y ) = 6/9 y
1/9 ( 10 ) = 10/9 or 1 1/9

Now we get the equation :
1 1/3y - 2/3 + 6/9y + 1 1/9

2- finding common denominators
1 1/3y and 6/9y can both have 9 as the denominator .
The fraction 1/3 has to be multiplied by 3 , both numerator & denominator , to get the same denominator (sorry if it’s confusing) .

Then we’d get 1 3/9y + 6/9y = 2y

Now we do the same thing with the other digits (without a variable)

- 2/3 + 1 1/9 or
- 6/9 + 1 1/9 = 4/9

3 - answer
So ,

1/3 (4y-2) + 1/9 (6y + 10 )

Distributed is

2y - 6/9

alukav5142 [94]3 years ago

3 0

The answers is 2y+4/9

Hope that helps!! :)

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Step-by-step explanation:

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= (cos3Ф - cos7Ф) sin3Ф ÷ 4cosФ

= 1/2(2cos3Ф sin3Ф) ÷ 4cosФ ∵cos7Ф = 0

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= (sin7ФcosФ - cos7ФsinФ) ÷ 8cosФ ∵sin7Ф = 1

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Hence, The correct prove will be:

$sin(\frac{\pi }{14})sin(\frac{3\pi }{14})sin(\frac{5\pi }{14})$ $= \frac{1}{8}$

Keywords: prove, sinФ, cosФ

Learn more about trigonometric functions from brainly.com/question/7331447

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