For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.
Hello! To solve this question, all you have to do is divide the total amount of parts made by the number of hours. 1116/7 is 159.42857 and other numbers, or 159 when rounded to the nearest whole number. There were about 159 parts made an hour.
D. W + 118=180 is the answer for the problem
Answer:
C = 11.18 D= 20
Step-by-step explanation:
Let's start with C
Square root both areas of the squares
Then use the Pythagoras Theorem: 
= C
Moving on to D
Square root both areas of the squares
29 is the hypotenuse, we are trying to find the other leg, so:
= D
