There is a type of ammo in f/o/r/t/n/i/t/e that can be magically used for every single gun. You open an ammo box, and out pops 141 rounds of that ammo. You have already collected 6 guns. How many rounds go into each gun?
The answer is 23.5
THERE IS A REMAINDER??
Nothing happens! Literally! It never happened! There is no ammo that can be used for all the guns. GG and hope to see you on the game sometime, cause...i am not allowed to have it.
Answer:
y=2
Step-by-step explanation:
first solve those in the brackets then find the square root
2y+3=11
put like terms together
3 goes to the right side
2y=11-3
2=8
y=4
√4=2
y=2
For this case we have the following expression:
(1 / x + 2) + (1 / x + 3) + (1 / X ^ 2 + 5 + 6)
Rewriting we have:
(1 / x + 2) + (1 / x + 3) + (1 / ((x + 2) * (x + 3)))
By doing common factor we have:
(1 / ((x + 2) * (x + 3))) * (x + 3 + x + 2 + 1)
Rewriting:
(1 / ((x + 2) * (x + 3))) * (2x + 6)
The sum is:
((2x + 6) / ((x + 2) * (x + 3)))
Answer:
((2x + 6) / ((x + 2) * (x + 3)))
The given number which is 2A193A411 is written in Base 11. Base 11 number is also called undecimal system. The digits of Base 11 number are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Since 10 is not accepted as a digit, then we have to substitute a variable which is A = 10. Hence, the digits of a Base 11 number are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and A.
Answer:
is 5668.3
Step-by-step explanation:
hope this helps
