Answer:
{58.02007 , 61.97993]
Step-by-step explanation:
Data are given in the question
Sample of cars = n = 121
Average speed = sample mean = 60
Standard deviation = sd = 11
And we assume
95% confidence t-score = 1.97993
Therefore
Confidence interval is
![= [60 - \frac{1.97993 \times 11}{\sqrt{121} }] , [60 + \frac{1.97993 \times 11}{\sqrt{121} }]](https://tex.z-dn.net/?f=%3D%20%5B60%20-%20%20%5Cfrac%7B1.97993%20%5Ctimes%2011%7D%7B%5Csqrt%7B121%7D%20%7D%5D%20%2C%20%20%5B60%20%2B%20%20%5Cfrac%7B1.97993%20%5Ctimes%2011%7D%7B%5Csqrt%7B121%7D%20%7D%5D)
= {58.02007 , 61.97993]
Basically we applied the above formula to determine the confidence interval
Is it for the fraction part? to get rid of the fractions just multiply both sides by the denominator.
Answer:
4712.39
Step-by-step explanation:
Answer:
<em>Hey mate, here's ur answer:</em>
<em>----------------------------------------------------------</em>
<em>(4a - 3b + 4c) + (8a - 2b + 3c)</em>
=4a+−3b+4c+8a+−2b+3c
=(4a+8a)+(−3b+−2b)+(4c+3c)
<u>=12a−5b+7c</u>
----------------------------------------------------------
<em>Hope it helps</em>
<em>#stayhomestaysafemate</em>
<em>:D</em>
Answer:
Only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.
Option A is correct.
Step-by-step explanation:
We will solve to find out Which expression has a positive quotient.
We know the division rule:
and 
We will use these rules
1) Negative three-fourths divided by Negative two-thirds

The quotient is positive.
2) Negative StartFraction 1 over 8 EndFraction divided by 3 and one-fifth

The quotient is negative.
3) 2 and StartFraction 2 over 7 EndFraction divided by negative one-fifth

The quotient is negative.
4) Negative 6 divided by Five-thirds

The quotient is negative.
So, only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.
Option A is correct.