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Pavlova-9 [17]
3 years ago
12

Hypertext Markup language (HTML) version _____ added support for style sheets to give web designers greater control over page la

yout and appearance.
Computers and Technology
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

4.01 version .

Explanation:

A hypertext Markup language is used for designing the web page when we added the CSS on the web page we can create the web page more efficient manner and also there is more control over the web page because we can easily call the classes of CSS.

The Hypertext Markup language version 4.01 provides greater flexibility on the web page also We can also control the page layout in a very easy manner. The appearance of the web page is good as compared to version HTML 4

You might be interested in
Write a function named print_backward that accepts a String as its parameter and prints the characters in the opposite order. Fo
noname [10]

Answer:

Here is the JavaScript code:

function print_backward(string) {

   var revString = "";

   for (var i = string.length - 1; i >= 0; i--) {

       revString += string[i];  }

   return revString; }

document.write(print_backward("hello there!"))

Explanation:

The function print_backward takes a string as a parameter.

Then it creates a new variable revString to hold a resultant string in opposite order.

The loop iterates through the characters of given string parameter in reverse and adds each character of the string to revString in opposite order.

Then the function returns revString which is the string in opposite order.

document.write(print_backward("hello there!")) This statement calls print_backward method passing a string hello there! to the method in order to print/display the characters of string in opposite order.

Lets say the string is hello

Then the loop works as follows:

The variable i is initialized to string.length - 1

string.length returns the length of the string

The length of string is 5 as there are 5 characters in string hello.

Hence string.length - 1 = 5 -1 = 4. So i=4

The loop checks if the value of i is greater than or equals to 0. This is true because i=4

Then the program enters the body of the loop which has a statement:

revString += string[i]; this works as:

revString = revString + string[i];

As i = 4 So

At first iteration

revString = revString + string[4];

This means the last character of string hello is added to revString. The last character of hello is 'o'

revString = 'o'

The statement in loop body continues to execute and stops when the value of i becomes less than 0.

The value of is decremented by 1 i.e. i-- So i = 3

At second iteration

revString = revString + string[3];

This means the second from last character of string hello is added to revString. The second last character of hello is 'l'

revString = 'ol'

The value of is decremented by 1 i.e. i-- So i = 2

At third iteration

revString = revString + string[2];

This means the third from last character of string hello is added to revString. The third last character of hello is 'l'

revString = 'oll'

The value of is decremented by 1 i.e. i-- So i = 1

At fourth iteration

revString = revString + string[1];

This means the fourth from last character of string hello is added to revString. The fourth last character of hello is 'e'

revString = 'olle'

The value of is decremented by 1 i.e. i-- So i = 0

At fifth iteration

revString = revString + string[0];

This means the fifth from last character of string hello is added to revString. The fifth last character of hello is 'e'

revString = 'olleh'

The value of is decremented by 1 i.e. i-- and the loop breaks because the i>=0 evaluates to false.

So the program moves to the next statement:

return revString;

revString = 'olleh' is returned and the statement document.write(print_backward("hello")) prints olleh on output screen.

In the given example the string is hello there! So this works same like the explained example and prints the following output on screen:

Output:

!ereht olleh

3 0
3 years ago
Which statements accurately describe tropical rain forests
sattari [20]

The tropical rain forest is a forest of tall trees in a region of year-round warmth. An average of 50 to 260 inches of rain falls yearly. Rain forests belong to the tropical wet climate group.

Explanation:

  • The temperature in a rain forest rarely gets higher than 93 °F or drops below 68 °F. The average humidity is between 77 and 88%, rainfall is often more than 100 inches a year. In monsoonal areas, there is a real dry season.
  • Rainforests now cover less than 6% of Earth's land surface. Tropical rainforests produce 40% of Earth's oxygen.
  • About 1/4 of all the medicines we use come from rainforest plants. Curare comes from a tropical vine, is used as an anesthetic and to relax muscles during surgery. Quinineis used to treat malaria.
  • There are four very distinct layers of trees in a tropical rain forest. They are the emergent, upper canopy, understory, and forest floor.
  • The soil of the tropical rainforests is shallow, poor in nutrients and without soluble minerals. Years of rainfall have washed away the nutrients in the soil obtained from weathered rocks.
  • The tropical rain forest can be found in three major geographical areas around the world.
  • Central America in the the Amazon river basin.  Africa - Zaire basin, with a small area in West Africa. Indo-Malaysia - west coast of India, Assam, Southeast Asia, New Guinea and Queensland, Australia.
7 0
3 years ago
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
3 years ago
A system might help managers to
Minchanka [31]

Answer:Decisions are only as valid as the information on which they are based. Management information systems improve your decision-making, because they provide information that is accurate, timely, relevant and complete.

Explanation:

Decisions are only as valid as the information on which they are based. Management information systems improve your decision-making, because they provide information that is accurate, timely, relevant and complete.

5 0
3 years ago
Which one of these is NOT a common use for hexadecimal numbers?
uysha [10]

Answer:

Boolean Values

Explanation:

Boolean Values are used as return values for functions to check whether something is true or false.

Hexadecimal numbers it is technique of representing numbers whose base value is 16.

The common use of Hexadecimal numbers are:

  1. To define memory locations .
  2. To define colors in web Pages .
  3. To represent error message.
  4. To represent MAC address
3 0
3 years ago
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