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3 years ago

10

26 divided by 5 1/2 I dont know!!

2 answers:

zavuch27 [327]3 years ago

5 0

Answer:

4.727

Step-by-step explanation:

An easy way to think of something being divided by a fraction is by turning the fraction into a decimal. In this case, it's 5 1/2, which is the same as 5.5. So, you can just calculate 26 / 5.5, by hand, or on a calculator, and the answer is 4.727.

<em>Hope this helps!</em>

gladu [14]3 years ago

5 0

Hey there!☺

$Answer:\boxed{4\frac{8}{11}}$

$Explanation:$

$26/5\frac{1}{2}$

Divide both fractions.

$26/5\frac{1}{2}=\frac{52}{11}$

52/11 needs to be simplified so let's simplify it.

$\frac{52}{11}=4\frac{8}{11}$

$4\frac{8}{11}$ is our final answer.

Hope this helps!

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Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

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We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

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Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

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Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

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Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

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Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

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3 years ago