Question

What is the value of x in the equation below?

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

The given equation is :

$1+2e^{x+1}=9$

Subtracting 1 in both sides

$1+2e^{x+1}-1=9-1$

$2e^{x+1}=8$

Dividing 2 in both sides

$e^{x+1}=\frac{8}{2}$

$e^{x+1}=4$

Taking log on both sides

$loge^{(x+1)}=log4$

$(x+1)loge=log4$

Plugging the value of log e as 1

$x+1=log4$

$x=log4-1$   ..................... Answer

Hope it will help :)