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kvv77 [185]
4 years ago
11

Calulate 1 and 4 over 5 -1 third over 2 and 2 fifth

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
5 0
\dfrac{1\dfrac{4}{5}-\dfrac{1}{3}}{2\dfrac{2}{5}}=\left(1\dfrac{4\cdot3}{5\cdot3}-\dfrac{1\cdot5}{3\cdot5}\right):\left(2\dfrac{2}{5}\right)=\left(1\dfrac{12}{15}-\dfrac{5}{15}\right):\dfrac{2\cdot5+2}{5}\\\\=1\dfrac{12-5}{15}:\dfrac{12}{5}=1\dfrac{7}{15}\cdot\dfrac{5}{12}=\dfrac{1\cdot15+7}{15}\cdot\dfrac{5}{12}=\dfrac{22}{15}\cdot\dfrac{5}{12}=\dfrac{11}{3}\cdot\dfrac{1}{6}\\\\=\dfrac{11}{18}
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Lerok [7]

I took the liberty of finding for the complete question. And here I believe that the problem asks for the half life of Curium. Assuming that the radioactive decay of Curium is of 1st order, therefore the rate equation is in the form of:

A = Ao e^(-kt)

where,

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Therefore the rate constant is:

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k = 0.0307/yr

 

The half life, t’, can be calculated using the formula:

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4 years ago
Line segment BD divides trapezoid ABCE into a rectangle and a right
grin007 [14]
<h3>Answer:  96 units</h3>

===========================================================

Explanation:

Since ABDE is a rectangle, the opposite sides AE and BD are the same length. This makes BD = 24. Similarly, ED = 20 since AB = 20.

Focus on triangle BCD. Let x be the length of segment CD. We can use the pythagorean theorem to find x

a^2 + b^2 = c^2

(BD)^2 + (CD)^2 = (BC)^2

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x = sqrt(49)

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Segment CD is 7 units long.

Since ED = 20, this means,

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P = 20+25+27+24

P = 96 units

Note that we didn't add in side BD as part of the perimeter because it is not an exterior side. Think of sides AB, BC, CE, and AE as outer walls of the house while BD is an interior wall. The perimeter is only worried about the outer walls.

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3 years ago
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Answer:

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Step-by-step explanation:

|x-99|<3

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Answer:

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