Answer: x=9,3
Step-by-step explanation:
Answer:
Option D. 2.51 is correct.
Step-by-step explanation:
Magnitude of first earthquake = 8.6
Let intensity of first earthquake be x

Magnitude of second earthquake = 8.2
Let intensity of second earthquake be y

Now, to find the factor by which intensity of first earthquake is greater than intensity of second : we divide equation (1) by equation (2)

Hence the required factor is 2.51
Therefore, Option D. 2.51 is correct.
so if you are asking for the distance do y2-y1/x2-x1
0-12/3-0
-12/3=-4
so -4 units
Answer: 299 m/s
Step-by-step explanation:
The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.
To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.
v(t) = 6t^2 + 5
Now input 7 in for t to find the velocity.
v(7) = 6(7)^2 + 5
v(7) = 299 m/s
Answer: I need more to solve this
Step-by-step explanation: