Answer:
5^0
Step-by-step explanation:
(5^3)^9 = 3 + 9 = 12
= 5^12
5^12/5^12 = 12 - 12 =0
5^0
brainliest is appreciated
56 / 8 = 7
7 * 10 = 70
She would have earned $70
So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
I think that you round to 9.80 seconds. Pardon me, I didn't understand the problem well
