1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
melomori [17]
2 years ago
11

Sylvie finds the solution to the system of equations by graphing.

Mathematics
1 answer:
Rina8888 [55]2 years ago
7 0

Answer:

The third graph is your answer.

Step-by-step explanation:

I included a graph below with the correct graphing.

You might be interested in
Perform the indicated operation. x+5/3 -x-3/2=
EastWind [94]

Step-by-step explanation:

to add or subtract in this case you have to the same common denominator. but what ever you do to the denominator you have to do to the numerator. top = numerator and bottom = denominator.

7 0
3 years ago
PLEASE HELP
Aleks04 [339]
Answer: 40%

=========================================

Work Shown:

"given that it's a senior" is an important piece of info that tells us to only focus on the "seniors" column. The word "given" is an indication that we know this information 100%

There are 5 seniors (2+3 = 5) and 2 of them are male. So 2/5 = 0.40 = 40% of the seniors are male. The probability of selecting a male, if we know this person is a senior, is 40%

3 0
2 years ago
Read 2 more answers
Here it is cherly not cherry ​
Fiesta28 [93]

Answer:

it is correct

Step-by-step explanation:

shown above in the photo

3 0
3 years ago
Read 2 more answers
What is the surface area of a box with the dimensions of length 4cm, width 3cm, and height 5cm? Only type the number - no units.
stich3 [128]

Answer:

heyy

Step-by-step explanation:

5 0
3 years ago
What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?
scoray [572]

Answer:

<u />\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:
\displaystyle \lim_{x \to c} x = c

Special Limit Rule [L’Hopital’s Rule]:
\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:
\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given limit</em>.

\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

  1. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}
  2. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

  1. [Limit] Apply Limit Rule [L' Hopital's Rule]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}
  2. [Limit] Differentiate [Derivative Rules and Properties]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}
  3. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}
  4. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}

∴ we have <em>evaluated</em> the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0
1 year ago
Other questions:
  • Find two consecutive even integers such that the square of the second, decreased by twice the first is 52
    12·1 answer
  • What percent of increase for a population that changed from 25,000 to 30,000
    11·2 answers
  • What is the solution set of the quadratic inequality 6x2+1&lt;0
    7·2 answers
  • The costs the company $0.02 per cubic inch of oatmeal to fill a container. The company does not want the new container to cost m
    6·2 answers
  • What 6x3 and 3x6 thankkkkkkkkkkkkkkkkk
    15·2 answers
  • Help with math problem​
    10·1 answer
  • 1/3 of all the trick or treaters that came to your house were dressed as characters from Star Wars. 3/5 of those
    12·2 answers
  • Which of the following is an example of natural selection?
    9·1 answer
  • An auditorium has rows of seats with a seats in each row Kayla
    12·1 answer
  • Express tan F as a fraction in simplest terms
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!