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Art [367]
3 years ago
8

Help me this is the last question i just need to know what to use to solve the problem

Mathematics
1 answer:
Genrish500 [490]3 years ago
8 0

Answer:

Not even one day

Step-by-step explanation:

I mean if it uses 4 bags a day  . . .

2/5's wont last long at all

You might be interested in
Help me please ASAP
Oliga [24]

Answer:

30

Step-by-step explanation:

if im reading the qestuion right

so she had 80 bucks she spend 20 on a ticked so she has 60 left so if im reading it right she spent all of her money so 60 divde by 2 is 30.  

hoped this helped!

3 0
3 years ago
you have $895 in your checking account and write checks for $669, plus take $100 in cash out of your account. How much do you ha
Scilla [17]
To answer this we just need to set up a equation:- 

895 - 669 - 100 = 126.

SO, after these transactions you will have $126 left. 

Hope I helped ya!! 
7 0
3 years ago
Calculating cos-1 ( help is gladly appreciated :) )
Alekssandra [29.7K]

Answer:

\frac{3\pi}{4}

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by \frac{180^\circ}{\pi} giving you:

\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}.

We can do this since \pi \text{ rad }=180^\circ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

\cos^{-1}(x) is going to output an angle measurement in [0,\pi].

So we are looking to solve the following equation in that interval:

\cos(x)=-\frac{\sqrt{2}}{2}.

This happens in the second quadrant on the given interval.

The solution to the equation is \frac{3\pi}{4}.

So we are saying that \cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2} implies \cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4} since \frac{3\pi}{4} \in [0,\pi].

Answer is \frac{3\pi}{4}.

4 0
3 years ago
For which function is the domain -6 is less than or equal to x less than or equal to -1 not appropriate? A) y=x^2 B) y=2x C) y=
elena-s [515]

Answer: idk jus needed the points so im answering

3 0
3 years ago
The model represents x2 – 9x + 14. An algebra tile configuration showing only the Product spot. 24 tiles are in the Product spot
klio [65]

I didn't get all the part with the tiles, but here's the general answer:

given a polynomial

p(x)=ax^2+bx+c

we have that x-k is a factor of p(x) if and only if k is a root of p(x), i.e. if

p(k)=ak^2+bk+c=0

So, given the polynomial

p(x)=x^2-9x+14

We can check if x-9 is a factor by evaluating p(9):

p(9)=81-81+14=14\neq 0

So, x-9 is not a factor.

Similarly, we can evaluate p(2),\ p(-5),\ p(-7) to check if x-2,\ x+5,\ x+7 are factors:

p(2)=4-18+14=0,\quad p(-5)=25+45+14=84\neq 0,\quad p(-7)=49+63+14=126 \neq 0

So, only x-2 is a factor of x^2-9x+14

4 0
3 years ago
Read 2 more answers
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