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Art [367]
3 years ago
8

Help me this is the last question i just need to know what to use to solve the problem

Mathematics
1 answer:
Genrish500 [490]3 years ago
8 0

Answer:

Not even one day

Step-by-step explanation:

I mean if it uses 4 bags a day  . . .

2/5's wont last long at all

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Please help ?????????
Murrr4er [49]

Answer:

B is your answer to this problem

Step-by-step explanation:

4 0
3 years ago
The temperature in a potter's kiln dropped 760 degrees in 4 hours.on what average,how much did the temperature drop per hour?
Elena L [17]
76 divided by 4 is 19. Add a zero and the answer is 190.
Hope this helps you !!
7 0
3 years ago
If a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?
pychu [463]
So convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5

50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8

area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5

407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet

the answer is 2075.7 ft^2 of seed
6 0
3 years ago
Read 2 more answers
sydney is cutting the crust from the edges of her sandwich. the dimensions, in centimeters, of the sandwich is shown. which expr
hodyreva [135]

Here we can see that the problem gives us the length of a sandwich of x = 1.2. The problem also asks us for the expression that better represents the approximate length of the crust given among the options above. Here we simply have to substitute x to each of the choices.


The answer is B) x = 8x² + 34; 45.52 centemiters


I hope it helps, Regards.

6 0
3 years ago
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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

3 0
3 years ago
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