Use d=vt to find the distance (d) where v= 105 and t = 3
2 answers:
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Answer:
The correct option is;
∠A ≅ ∠X
Step-by-step explanation:
The given coordinates of the points of triangle ACB are;
A(-4, 4), C(-1, 3), B(-4, 0)
The given coordinates of the points of triangle XYZ are;
X(0, 8), Y(8, 8), Z(6, 2), therefore, we have
The length. l. of segment is given by the following formula;
For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)
For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4
For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2
For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8
For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2
For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10
Therefore;
XY ~ AB, XZ ~ BC, ZY ~ AC
Which gives;
∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z
Answer:
44.1m
Step-by-step explanation:
we are given a quadratic function which represents the height and time of a baseball
we want to figure out maximum height of
the baseball
since the given function is a quadratic function so we have a parabola
which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)
to do so we can use some special formulas
recall that,
notice that, our given function is not in standard form i.e
let's make it so
therefore we got
our <em>a</em> is -4.9 and <em>b </em>is 29.4
so substitute:
remove parentheses and change its sign:
simplify multiplication:
simplify division:
so we have figured out the time when the baseball will reach the maximum height
now we have to figure out the height
to do so
substitute the got value of time to our given function
simplify square:
simplify mutilation:
simplify substraction:
hence,
the maximum height of the baseball is 44.1 metres
