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3 years ago

Factor this expression completely. Write the factored expression in the space provided.

Mathematics

1 answer:

icang [17]3 years ago

5 0

<h3>I'll teach you how to solve y^2 - y - 12</h3>

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y^2 - y - 12

Break the expression into groups:

(y^2+3y)+(-4y-12)

Factor out y from y^2+37:

y^2+37 = y(y+3)

Factor out -4 from -4y-12:

-4y-12 = -4(y+3)

y(y+3)-4y-12

Factor out common term y+3:

(y+3)(y-4)

Your Answer Is (y+3)(y-4)

plz mark me as brainliest :)

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3 years ago

Can someone help me out with this? I’m not sure what I’m doing wrong.

Nadusha1986 [10]

Answer:

Step-by-step explanation:

This is a system of inequalities such that:

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Let's start by solving for y for both equations:

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$2x+3y\geq 2\\\\3y\geq -2x+2\\\\y \geq \frac{-2x+2}{3}$

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Now if we substitute the 2nd y into the first equation we obtain:

$2x+3(\frac{3x-3}{4}) \geq 2\\\\2x+\frac{9x-9}{4}\geq 2\\\\\frac{8x+9x-9}{4}\geq 2\\\\17x-9\geq 8\\\\17x\geq 17\\\\x\geq 1$

Now we will solve for the second equation using the first result of y and we obtain:

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And so our solution for the system of equations is:

$x \leq 1\\and \\y\geq \frac{-2x+2}{3}$

As well as:

$x>1\\and\\y\geq \frac{3x-3}{4}$

4 0

4 years ago