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taurus [48]
3 years ago
12

Factor this expression completely. Write the factored expression in the space provided.

Mathematics
1 answer:
icang [17]3 years ago
5 0
<h3>I'll teach you how to solve y^2 - y - 12</h3>

--------------------------------------------------

y^2 - y - 12

Break the expression into groups:

(y^2+3y)+(-4y-12)

Factor out y from y^2+37:

y^2+37 = y(y+3)

Factor out -4 from -4y-12:

-4y-12 = -4(y+3)

y(y+3)-4y-12

Factor out common term y+3:

(y+3)(y-4)

Your Answer Is (y+3)(y-4)

plz mark me as brainliest :)

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I need help please. I don't get how to do systems of linear equations!!!!!!!
taurus [48]
The soluition set is (-3,5) and a normal ordered pair reads (x,y). So that means 5 = [_]x-10
-Add 10 to both sides
15 = [_]x
-And we know the value of x so lets sub that in.
15 = [_](-3)
-And now we divide by -3
-5 = [_]

Next we have 3x-[_]y=-19
-Lets start this buy substituting values of x and y into the equation again.
3(-3)-[_](5)=-19
-Simplify
-9 - [_](5) = -19
-Move the (-9) by adding 9 to both sides
-[_](5) = -10
-divide by 5 = -2
-(1)[_] = -2
[_] = 2
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Step-by-step explanation:

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A=1/(2s) * (v²-u²)




.......,.........
..


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PLEASSE HELP URGENT WILL GIVE BRAINLIEST FOR CORRECT ANSWER Brian wanted to find out if studying for the algebra test is effecti
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