Rachel is going on a trip to Japan. The table below shows the cities she hopes to visit during her stay, as well as the amount

Mathematics

1 answer:

Bond [772]3 years ago

8 0

Answer:

C. Osaka and Sendai

Step-by-step explanation:

I would start off by first adding up the total cost of going to all of the cities. This would equal ¥ 49,644. Next I would find the total cost for each answer choice.

A. Nara and Sapporo = ¥ 12,930 - ¥36,000 = ¥ 36,714

B. Hiroshima and Kyoto = ¥ 13,379 - ¥36,000 = ¥ 36,265

C. Osaka and Sendai = ¥ 14,665 - ¥36,000 = ¥ 34,979

(I am unable to find 'D', What is Connora?)

With this we are able to see that with what I was able to find, C would be the best choice.

You might be interested in

Morre Math HARDDDDDDDD

Dafna11 [192]

Answer:

the person above is right it's 4.5 units

give them the crown

7 0

2 years ago

Simplify. express the answer using positive -5w^4y^-2\-15w^-6y^2

Ymorist [56]

Simplified. Employ photomath for more detailed explanation.

7 0

3 years ago

Read 2 more answers

Mrs Rivas bought a can of paint he used 3/8 of paint and 1/4 he also used some for a birdhouse and had 1/8 of paint left how muc

Degger [83]

Answer:

The amount of paint used in the birdhouse = (1/4) of paint

Step-by-step explanation:

The amount of paint used in first go = 3/8

The amount of pain used in second go = 1/4

The amount of paint used in bird house = k

The amount paint left = 1/8

Now, according to the question:

Paint used in ( First go + second go + Birdhouse) + Paint left = 1 can Paint

⇒ $\frac{3}{8} + \frac{1}{4} + k + \frac{1}{8} = 1\\\implies \frac{3 + 1(2) + 1}{8} + k = 1\\ \frac{6}{8} + k = 1 \\\implies k = 1 - \frac{6}{8} = \frac{8-6}{8} = \frac{2}{8} = \frac{1}{4} \\\implies k = \frac{1}{4}$