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2 years ago

3w^45x^8w^7*2x

Mathematics

1 answer:

dexar [7]2 years ago

3 0

Answer:

The simplified expression is $30w^{11}x^9$

Therefore the simplified expression to the given expression is $3w^4.5x^8w^7.2x=30w^{11}x^9$

Step-by-step explanation:

Given expression is $3w^4.5x^8w^7.2x$

To simplify the given expression as below :

$3w^4.5x^8w^7.2x$

First combine the like terms to simplify the expression easily we get

$=(3.5.2)(w^4.w^7)(x^8.x)$

$=30(w^{4+7})(x^{8+1})$ ( by using the property $a^m.a^n=a^{m+n}$ )

$=30w^{11}x^9$

Therefore the simplified expression is $30w^{11}x^9$

Therefore the simplified expression to the given expression is $3w^4.5x^8w^7.2x=30w^{11}x^9$

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A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5

gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5 minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0

2 years ago

URGENT! WILL MARK BRAINLIEST!

Sergeu [11.5K]

Answer:

Hi! Your answer will be : 599.37!

Step-by-step explanation:

8 0

3 years ago

Help!! Thank you so much!!

Orlov [11]

The volume we're looking for is the volume of both cones in the figure.

The volume of a cone is $V=\pi r^2\frac{h}{3}$ .

So, $V_{tot} = V_{1} + V_2$ .

Cone 1's variables:

r = 2.6

h = 5

Cone 2's variables:

r = 2.6

h = 3

Now we can just plug and chug!

$V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68$

V = c. 56.6 cubic units

5 0

2 years ago

Averi estaba intentando factorizar 4x^2+20x-164x

Darina [25.2K]

Responder:

El ancho del modelo de área de Averi será x² + 5x-4

Explicación paso a paso:

Deje que el área del modelo de Averi sea igual a la ecuación dada

4x² + 20x-16

Si el mayor factor común del modelo es 4, esto significa que 4 se puede factorizar fácilmente de la ecuación como se muestra;

4 * (x² + 5x-4) ... (1)

Si la fórmula para el modelo de área = Largo * Ancho

Al comparar la fórmula para encontrar el área del modelo con la ecuación 1, el ancho del modelo de área será la función entre paréntesis, es decir,

x² + 5x-4

El ancho del modelo de área de Averi será x² + 5x-4

3 0

3 years ago

What is the factored form of the expression x^2-2x-15?

Dimas [21]

Answer:

$(x-5)(x+3)$

Step-by-step explanation:

Factor by grouping

$x^2-2x-15\\x^2+3x-5x-15\\x(x+3)-5(x+3)\\(x-5)(x+3)$

5 0

2 years ago

3w^4*5x^8*w^7*2x

3w^45x^8w^7*2x