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3 years ago

Find the area of the shaded region.

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

3 0

1. If we join another radius to the shaded area, we will notice that the triangle has all sides 4 units, making it an equilateral triangle.

2. Equilateral triangle has all angles 60°

Area of 1 sector = 60/360 x π (4)² = 8.38 units²

$\text {Area of equilateral triangle =} \dfrac{\sqrt{3}}{4} \text{(4)}^2 = 6.93 \text{ units}^2$

Area of 1 shaded part = 8.38 - 6.93 = 1.45 units²

Area of all shaded part = 1.45 x 2 = 2.9 units²

Answer: 2.9 units²

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Find the areas of the trapezoids

Sholpan [36]

Answer:

12 units²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 4 ( perpendicular distance between the bases ) and

b₁ = SR = 2, b₂ = TA = 4 , then

A = $\frac{1}{2}$ × 4 × (2 + 4) = 2 × 6 = 12 units²

5 0

2 years ago

May I have some help?

chubhunter [2.5K]

For whatcha problem hun

8 0

3 years ago

Work out the height of a parallelogram with a base of 10m and an area of 60m2

noname [10]

Area formula of a parallelogram is
A = base x height

Given are the
Area = 60 m² and base = 10 m

Substitute the given:

60 = 10h (divide by 10 to find value of h)
$\frac{60}{10} = \frac{10h}{10}$ (10 and 10 cancels out)

h = 6
The height of a parallelogram with a base of 10m and an area of 60m² is 6m

3 0

3 years ago

I only need 12 and 17, first good response i will give brainliest please i’m desperate

Mumz [18]

Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$

Substitute the y-intercept and the point (4, 3) into the slope-intercept formula and solve for <em>m</em> to find the slope:

$\implies y=mx+b$

$\implies -3=m(4)-2$

$\implies -1=4m$

$\implies m=-\dfrac{1}{4}$

Therefore, the equation of the line is:

$y=-\dfrac{1}{4}x-2$

7 0

10 months ago

Can someone help with this please

grigory [225]

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients. The polynomial is x³- 7x² - 6x + 72.

<h3>What is a polynomial?</h3>

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.

The polynomial using the given information can be made as shown below.

Given the zeros of the polynomial are -3, 4, and 6.

P(x) = (x+3)(x-4)(x-6) = x³- 7x² - 6x + 72

To check the end behaviour of the function, the graph of the function can be plotted as shown in the below image.

Hence, the polynomial is x³- 7x² - 6x + 72.

Learn more about Polynomials:

brainly.com/question/27343162

#SPJ1

4 0

2 years ago