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S_A_V [24]
3 years ago
6

Which of the following is not part of active listening?

Computers and Technology
2 answers:
Taya2010 [7]3 years ago
6 0

Answer: agreeing with what the other person has said

Explanation: Just mindlessly agreeing to what the other person is saying is not active listening, Restating what you heard in your own words, asking clarifying questions, and listening for the emotions the other person has expressed are all part of being an active listener.

Hope this helps!  :)

Sergeeva-Olga [200]3 years ago
4 0

Answer: B

Explanation:

Agreeing could possibly mean your not paying much attention and is like yeah ,yup, even though you are not paying attention

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About.com is considered a (an):
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7 0
3 years ago
Assume in the for loop header, the range function has the three arguments: range (1, 10, 3), if you were to print out the value
Licemer1 [7]

Answer:

1, 4, 7

Explanation:

The instruction in the question can be represented as:

for i in range(1,10,3):

   print i

What the above code does is that:

It starts printing the value of i from 1

Increment by 3

Then stop printing at 9 (i.e.. 10 - 1)

So: The sequence is as follows

Print 1

Add 3, to give 4

Print 4

Add 3, to give 7

Print 7

Add 3, to give 10 (10 > 10 - 1).

So, it stops execution.

6 0
2 years ago
What does coding mean​
NeTakaya
The process or activity of writing computer programs.
3 0
3 years ago
Read 2 more answers
Cathy designed a website for a cereal brand. When users view the website, their eyes first fall on the brand name, then they vie
PSYCHO15rus [73]

Answer:

dominance

Explanation:

i just took it and got it right

4 0
2 years ago
In a switch statement, if a break statement is missing, _______________. Select one: a. the default case is automatically execut
Aleks [24]

Answer:

c. execution falls through the next branch until a break statement is reached

Explanation:

In a switch statement, if break is missing, then program continues to the next cases until it finds a break statement.

Consider the following example!

Example:

#include <iostream>

using namespace std;

int main()

{

  int choice = 1;

  switch (choice)

  {

      case 1:

      printf("This is case 1, No break\n");

      case 2:

      printf("This is case 2, No break\n");

      case 3:

      printf("This is case 3, with break\n");

      break;

      default: printf("Error! wrong choice\n");

  }

  return 0;

}

Output:

This is case 1, No break

This is case 2, No break

This is case 3, with break

We have 3 cases here and case 1 and 2 don't have break statements, only case 3 has a break statement.

We called the case 1, then program continued to case 2,  and finally to case 3 where it finds the break statement and terminates.

Therefore, we conclude that in a switch statement, if a break statement is missing, then execution falls through the next branch until a break statement is found.

8 0
3 years ago
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