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solniwko [45]
3 years ago
13

Evaluate f-2g for f = 3 and g = 27.

Mathematics
1 answer:
lyudmila [28]3 years ago
7 0
If you would like to evaluate f - 2 * g for f = 3 and g = 27, you can do this using the following step:

f - 2 * g = 3 - 2 * 27 = - 51
The correct result would be - 51.

If you would like to evaluate x * 0 + y * 0 for x = 3 and y = 2, you can do this using the following step:

x * 0 + y * 0 = 3 * 0 + 2 * 0 = 0 + 0 = 0
The correct result would be 0.
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Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
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The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
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Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

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For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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