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Oksi-84 [34.3K]
4 years ago
7

Hey! If you can help here it is!

Mathematics
1 answer:
Amanda [17]4 years ago
6 0

Answer:

x=3,x=-1

Step-by-step explanation:

Start with:

x(x-1)-3(x-3)+3(x-2)=x+6

Distribute the values on the outside of each of the parentheses.

x^2-x-3x+9+3x-6=x+6

Combine like terms.

x^2-x+3=x+6

Subtract 6 from both sides of the equation.

x^2-x-3=x

Subtract x from both sides of the equation.

x^2-2x-3=0

Now, we need to use our quadratic equation formula:

ax^2+bx+c=0

x= \frac{-b+/-\sqrt{b^2-4ac}}{2a}

Identify your values.

a=1\\b=-2\\c=-3

Substitute.

(Solve positive)

x= \frac{-(-2)+\sqrt{(-2)^2-4(1)(-3)}}{2(1)}

Solve.

x= \frac{2+\sqrt{(16}}{2}

Find the square root of 16.

x=\frac{2+4}{2}

Add.

x=\frac{6}{2}

Simplify.

x=3

~

(Solve negative)

x= \frac{-(-2)-\sqrt{(-2)^2-4(1)(-3)}}{2(1)}

Solve.

x= \frac{2-\sqrt{(16}}{2}

Find the square root of 16.

x=\frac{2-4}{2}

Subtract.

x=\frac{-2}{2}

Simplify.

x=-1

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