15) 4m^2
17)9n^6
198a^2 (^ = power of)
Simplify the following:
sqrt(378904)
sqrt(378904) = sqrt(8×47363) = sqrt(2^3×47363):
sqrt(2^3 47363)
sqrt(2^3 47363) = sqrt(2^3) sqrt(47363) = 2 sqrt(2) sqrt(47363):
2 sqrt(2) sqrt(47363)
sqrt(2) sqrt(47363) = sqrt(2×47363):
2 sqrt(2×47363)
2×47363 = 94726:
Answer: 2 sqrt(94726)
Answer:
100
Step-by-step explanation:
Mixed candy question... Skittles jar... to be filled with Jelly beans.
Let's first calculate the volume of the jar. We'll assume it's a regular cylindrical prism jar, unlike the one on the photo which is narrower on top.
V = π * r² * h = π * (3.5)² * 11.5 = 140.875 π = 442.6 cubic cm
Now, we don't have the precise measurement of a jelly bean, but we know it's roughly 2-3 cubic cm. The precision isn't needed to answer this question, just to have a rough idea... it's no 300 cu cm per jelly bean.
So, let's assume a 3 cu cm per jelly bean (2 cu cm wouldn't the final answer)....
442.6 / 3 = 147.5 jelly beans, approximately.
So, can they fit 100,000? No
Can we fit 10,000 in there? No
Can we fit 100? Yes.
Can we fit 1? Certainly
The most reasonable lower-limit would then be 100.
Answer:
3/5
Step-by-step explanation:
Cos(B) = adjacent/hypotenuse
Cos(B) = 48/80 = 6/10
Cos(B) = 3/5 or 0.6
