Question

X + y + w = b

Answer 1

Answer:

(a) a=6 and b≠$\frac{11}{4}$

(b)a≠6

(c) a=6 and b=$\frac{11}{4}$

Step-by-step explanation:

writing equation in agumented matrix form

$\begin{bmatrix}1 &1 & 0 &1 &b\\ 2 &3 & 1 &5 &6\\ 0& 0 & 1 &1 &4\\ 0& 2 & 2&a &1\end{bmatrix}$

now $R_{2} =R_{2}-2\times R_{1}$

$\begin{bmatrix}1 &1& 0 &1 &b\\ 0 &1& 1 &3 &6-2b\\ 0& 0 & 1 &1 &4\\ 0& 2 & 2&a &1\end{bmatrix}$

now $R_{4} =R_{4}-2\times R_{2}$

$\begin{bmatrix}1 &1& 0 &1 &b\\ 0 &1& 1 &3 &6-2b\\ 0& 0 & 1 &1 &4\\ 0& 0 & 0 &a-6 &4b-11\end{bmatrix}$

a) now for inconsistent

rank of augamented matrix ≠ rank of matrix

for that  a=6 and b≠$\frac{11}{4}$

b) for consistent w/ a unique solution

rank of augamented matrix = rank of matrix

  a≠6

c) consistent w/ infinitely-many sol'ns

  rank of augamented matrix = rank of matrix < no. of variable

for that condition

 a=6 and b=[tex]\frac{11}{4}

then rank become 3 which is less than variable which is 4.