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3 years ago

70 decreased by 80% in math

1 answer:

7 0

The answer for your math problem is 55.2. To get this, you do 70 times 0.80, which gives us 56. Then, subtract it by 0.80.

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What is the answer to this question

vlada-n [284]

Answer:

Step-by-step explanation:

If you calculate the side of a square using pythagorean theorem, you would get a side length of sqrt37. Simple multiply this by 4

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3 years ago

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Identify the zeros of f(x)=(x-7)(x+4)(3x-2)

alexgriva [62]

To find the zero you must set each factor equal to zero and solve for for x like so...

Factor (x - 7)

x - 7 = 0

x = 7

Factor (x + 4)

x + 4 = 0

x = -4

Factor (3x - 2)

3x - 2 = 0

3x = 2

x = $\frac{2}{3}$

All the zeros are:

-4, $\frac{2}{3}$ , 7

Hope this helped!

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3 years ago

Jill has a 25% off coupon for some computer software. If the coupon saved her $35, how much would the software cost without the

zysi [14]

Answer:

$140

Step-by-step explanation:

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3 years ago

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Olenka [21]

Answer:

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Step-by-step explanation:

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3 years ago

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Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

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3 years ago