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astra-53 [7]
3 years ago
5

Please help select both answers!!

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
I am pretty sure it is 2 units to the left of g(x).
krok68 [10]3 years ago
5 0
I think it would be the first one? 2 units to the left of g(x).
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Calculate the area of triangle ABC with altitude CD, given A (6, -2), B (1, 3), C (5, 5), and D (2, 2).
Flura [38]

Answer:

15 units

Step-by-step explanation:

I just took this geometry test with the same question. Its 15

3 0
3 years ago
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In a class of 22 students, 15 play an instrument and 11 play a sport. There are 9
ollegr [7]

Answer:7/22

Sorry I don’t know how to explain.But here the answer.

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6 0
2 years ago
Help me please !!!!!!! : P
Marizza181 [45]
The answer would be (-5+_sqroot(-3))/2 which are answers A and F
7 0
3 years ago
Pls help
KATRIN_1 [288]

Answer:

169.04 in² (nearest hundredth)

Step-by-step explanation:

Surface area of a cone = \pir² + \pirl

(where r = radius of the base and l = slant height)

Given slant height l = 10 and surface area = 188.5

Surface area  = \pir² + \pirl

188.5 = \pir² + 10\pir

\pir² + 10\pir - 188.5 = 0

r = \frac{-10\pi +\sqrt{(10\pi )^2-(4\times\pi \times-188.5)} }{2\pi } = 4.219621117...

Volume of a cone = (1/3)\pir²h

(where r = radius of the base and h = height)

We need to find an expression for h in terms of l using Pythagoras' Theorem a² + b² = c², where a = radius, b = height and c = slant height

r² + h² = l²

h² = l² - r²

h = √(l² - r²)

Therefore, substituting found expression for h:

volume of a cone = (1/3)\pir²√(l² - r²)

Given slant height l = 10 and r = 4.219621117...

volume = 169.0431969... = 169.04 in² (nearest hundredth)

5 0
2 years ago
Read 2 more answers
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
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