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mafiozo [28]
3 years ago
7

14 g=26 how do you solve this problem n cause it is to hard

Mathematics
1 answer:
Gwar [14]3 years ago
4 0
Well i need more details in order to help you!!
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Fifty less than three times a number is -20. Find the number.
Mrrafil [7]
3x - 50 = -20
Add 50 to both sides
3x = 30
x = 10
The number is 10
8 0
3 years ago
Read 2 more answers
PLS HELP !!
Oliga [24]
For this case we have that the weight of the bouquet of flowers will be:
 4.3 * 10 ^ 4 - 2 * (7.5 * 10 ^ 2)
 Rewriting we have:
 4.1 * 10 ^ 4 miligrams
 Thus, we have that the values of p and q are given by:
 p = 4.1
 q = 4
 Answer:
 
4.1 * 10 ^ 4 miligrams
 
p = 4.1
 
q = 4
8 0
3 years ago
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Imagine that you have the opportunity to purchase a large piece of land for $100,000, after taking out a loan. You have decided
MakcuM [25]

what is this

Step-by-step explanation:

Option #1 – charges 5% simple interest per year; this is a short-term loan for only 5-years.

Option #2 – charges 7% simple interest per year; this is a short-term loan for only 3-years.

Option #3 – charges 3.2% simple interest per year; there is no time limit on this loan (as a group determine how long you think it will take you to make enough money to be able to pay back the loan with interest)

Option #4 - charges 10% simple interest per year; only lasts 10 months

Option what is this

3 0
3 years ago
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Heeeeelp Find the distance of AB if A (2, 6) and B (-5, 2).
evablogger [386]

Answer:

let A (2, 6) be (x1, y1)

B (-5, 2)  be (x2, y2)

distance AB =√[(x2 - x1)² + (y2 - y1)²]

                    √[(-7)²+ (-4)²]

                   √65

                   

7 0
3 years ago
In triangle ABC, angle C is a right angle and BC=5. If measure of angle B = 30 degrees, find AC
Nina [5.8K]
Answer = d

using the 30 - 60 - 90 triangle theorem

side across from the angle

across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x

BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it

x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom

x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3

since side BC is x
BC = 5 sqrt 3/ 3

* Drawing the triangle diagram would help*
5 0
3 years ago
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