Answer:
![\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5By%7C-2%20%E2%89%A4%20y%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%20%E2%88%9E%29%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C-4%20%E2%89%A4%20x%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-4%2C%20%E2%88%9E%29)
Explanation:
<em>See above graph</em>
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Answer:
<h2>V = 729</h2>
Step-by-step explanation:
The formula of a volume of a cube with an edge <em>a</em>
<h3>
V = a³</h3>
We have <em>a </em>=<em> </em>9 . Substitute:
<h3>V = 9³ = 9 · 9 · 9 = 729</h3>
Well for the function of x we have x=t^5+1 and we know t= -1
So you plug in -1 instead of the t and you will get x=(-1)^5+1
Now just resolve that equation to get the value of x
x = (-1)^5+1 = -1+1 = 0 So x=0
Do the same with y and you’ll get y=2
30 divided by 7 is 4.2z
It snowed 4.2 inches per hour
a)
FH = 102, FG = 5x + 9. HG = 9x - 5 <em>Given</em>
FG + HG = FH <em>Segment addition postulate</em>
5x + 9 + 9x - 5 = 102 <em>Substitution</em>
14x + 4 = 102 <em>Simplify (added like terms)</em>
14x = 98 <em>Subtraction property of equality</em>
x = 7 <em>Division property of equality</em>
b) FG = 5x + 9 = 5(7) + 9 = 35 + 9 = 44
c) HG = 9x - 5 = 9(7) - 5 = 63 - 5 = 58
Answers: a = 7, b = 44, c = 58
