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3 years ago

14

there are 91 threatened and endangered plants and animals in Texas write and solve an equation to find the number of threatened

and endangered animals if there are 28 threatened and endangered plants

1 answer:

TEA [102]3 years ago

3 0

$\sf 91 - 28 = threatened~and~endangered~animals\\threatened~and~endangered~animals= 63$

Your answer is 63.

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Valerie ran Three and one-fourth laps yesterday, and her coach wants her to run Two and one-half times that many laps today. How

Maru [420]

Answer:

13/4 * 5/2

Step-by-step explanation:

In the question, it says that her coach wants her to run 2 1/2 TIMES the original 3/4 she had ran. Therefore, you would want to make the fractions into improper fractions, and then multiply, which is how you would get 13/4 * 5/2.

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2 years ago

HELP ME PLEASEEEEEEEEEEEE

olga nikolaevna [1]

Answer:

L

Step-by-step explanation:

The first number is always x-coordinate. And amongst all only J and L has positive x-coordinates. With J y-coordinate is also positive so it should be L

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2 years ago

There are 240 blocks and they take half of the blocks

natulia [17]

There are 120 blocks left.

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2 years ago

What the percent increase from 18 to 26

mina [271]

26-18=8. 8/18=4/9=44.444 (repeating)%

6 0

2 years ago

Blake is playing a racing game on his computer. The game tracks the locations of objects using and y coordinates (see graph belo

Anvisha [2.4K]

<h3>Answer: 2.2 units</h3>

============================================

Explanation:

I'll define these point labels

B = Blake's starting position
F = finish line
C = the third unmarked point of the triangle

The locations of the points are

B = (-8,1)
C = (-6,-3)
F = (4,-2)

Use the distance formula to find the distance from B to C

$B = (x_1,y_1) = (-8,1) \text{ and } C = (x_2,y_2) = (-6,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-8-(-6))^2 + (1-(-3))^2}\\\\d = \sqrt{(-8+6)^2 + (1+3)^2}\\\\d = \sqrt{(-2)^2 + (4)^2}\\\\d = \sqrt{4 + 16}\\\\d = \sqrt{20} \ \text{ ... exact distance}\\\\d \approx 4.47214 \ \ \text{... approximate distance}\\\\$

Segment BC is roughly 4.47214 units long.

Following similar steps, you should find that segment CF is approximately 10.04988 units long.

If Blake doesn't take the shortcut, then he travels approximately BC+CF = 4.47214+10.04988 = 14.52202 units. This is the path from B to C to F in that order.

---------

Use the distance formula again to find the distance from B to F. This distance is about 12.36932 units. He travels this amount if he takes the shortcut.

Subtract this and the previous result we got

14.52202 - 12.36932 = 2.1527

That rounds to 2.2

This is the amount of distance he doesn't have to travel when he takes the shortcut.

In other words, the track is roughly 2.2 units shorter when taking the shortcut.

Side note: Replace "units" with whatever units you're working with (eg: feet or meters).

7 0

2 years ago