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krek1111 [17]
3 years ago
15

At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The sta

tistician reported that the mean serve speed was 100 miles per hour (mph) and the standard deviation of the serve speeds was 15 mph. If nothing is known about the shape of the distribution, what percentage of the player's serve speeds are less than 70 mph?
Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

2.275%

Step-by-step explanation:

We solve this question using z score formula

z = (x-μ)/σ,

where

x is the raw score = 70 mph

μ is the population mean = 100 mph

σ is the population standard deviation = 15 mph

z score = 70 - 100/15

z score = -30/15

z score = - 2

Determining the Probability value from Z-Table:

P(x ≤ 70) = P(x < 70)

= P(z = -2)

= 0.02275

Hence the probability of the player's serve that are less than 70 mph is 0.02275

Converting it to percentage

= 0.02275 × 100

= 2.275%

Therefore, the percentage of the player's serve speeds that are less than 70 mph is = 2.275%

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Answer:

4/5

Step-by-step explanation:

Of the hats in Deb's Hat Shop, 1/2 are purple and another 3/10 are red. What fraction of the hats are either purple or red?

The Fraction of the hats that are either purple or red are:

Purple + Red

= 1/2 + 3/10

Lowest Common Denominator is 10

= 5 + 3/10

= 8/10

= 4/5

Therefore, the fraction of the hats tha are either purple or red is 4/5

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One year ago, Lindsey deposited $250 into a savings account. Her balance is now $253. Two years ago, Jenn deposited $250 into a
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Answer:

8/24

Step-by-step explanation:

8/24 is equal to 2/6.

8/24  -->  4/12  -->  2/6

The numerator of 8/24 (8) is less then the denominator (24) by 16.

24 - 16 = 8  

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What is the name of the plane formed when two perpendicular number lines intersect?<br>​
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8 0
3 years ago
Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,
lukranit [14]

Answer:

Option B is correct.

It is reasonable to believe that the mean magnesium ion concentration may be greater than 199.5 as the confidence interval obtained contains values that are greater than 199.5

Step-by-step explanation:

Complete Question

Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply, with the following results. It is reasonable to assume that the population is approximately normal.

170 201 199 202 173 153

Based on a 95% confidence interval for the mean magnesium ion concentration, is it reasonable to believe that the mean magnesium ion concentration may be greater than 199.5? (Hint: you should first calculate the 95% confidence interval for the mean magnesium ion concentration.)

A) The likelihood cannot be determined.

B) Yes

C) No

Solution

For this question, obtaining the confidence interval will give a clear solution to the problem.

Since the Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence, if the range obtained contains values greater than the standard we are comparing against (199.5), then the confidence interval proves that the mean magnesium ion may be greater than 199.5.

But to obtain the confidence interval, we need the mean and standard deviation for the sample.

170, 201, 199, 202, 173, 153

Mean = (sum of variables)/(total number of variables)

Sum of variables = 170+201+199+202+173+153 = 1098

Total number of variables = 6

Mean = (1098/6) = 183

Standard deviation = σ = √[Σ(x - xbar)²/N]

x = each variable

xbar = mean = 183

N = number of variables = 6

Σ(x - xbar)² = (170-183)² + (201-183)² + (199-183)² + (202-183)² + (173-183)² + (153-183)²

= 169 + 324 + 256 + 361 + 100 + 900

= 2110

σ = √(2110/6) = 18.75

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 183

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 6 - 1 = 5.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 5) = 2.57 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 18.75

n = sample size = 6

σₓ = (18.75/√6) = 7.656

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 183 ± (2.57 × 7.656)

CI = 183 ± 19.675

95% CI = (163.325, 202.675)

95% Confidence interval = (163.3, 202.7)

It is reasonable to believe that the mean magnesium ion concentration may be greater than 199.5 as the confidence interval obtained contains values that are greater than 199.5

Hope this Helps!!!

8 0
3 years ago
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