Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,
![x^2=1440000+2890000-4080000*0.615661475](https://tex.z-dn.net/?f=x%5E2%3D1440000%2B2890000-4080000%2A0.615661475)
![x^2=4330000-2511898.81933008](https://tex.z-dn.net/?f=x%5E2%3D4330000-2511898.81933008)
![x^2=1818101.18066992](https://tex.z-dn.net/?f=x%5E2%3D1818101.18066992)
Let us take square root of both sides of our equation.
![x=\sqrt{1818101.18066992}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B1818101.18066992%7D)
![x=1348.3698234\approx 1348](https://tex.z-dn.net/?f=x%3D1348.3698234%5Capprox%201348)
Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
Answer:
Step-by-step explanation:
The goal to solving any equation is to have x = {something}. That means we need to get the x out from underneath that radical. It's a square root, so we can "undo" it by squaring. Square both sides because this is an equation. Squaring both sides gives you
![x^2=-3x+40](https://tex.z-dn.net/?f=x%5E2%3D-3x%2B40)
Get everything on one side of the equals sign and set the quadratic equal to 0:
![x^2+3x-40=0](https://tex.z-dn.net/?f=x%5E2%2B3x-40%3D0)
Throw this into the quadratic formula to get that the solutions are x = 5 and -8. We need to see if only one works, both work, or neither work in the original equation.
Does
?
and
![5=\sqrt{25}](https://tex.z-dn.net/?f=5%3D%5Csqrt%7B25%7D)
and 5 = 5. So 5 works. Let's try -8 now:
and
so
![-8=\sqrt{64}](https://tex.z-dn.net/?f=-8%3D%5Csqrt%7B64%7D)
-8 = 8? No it doesn't. So only 5 works. Your choice is the third one down.
Answer:
t = 8
Step-by-step explanation:
Answer:
9 gallons of water per minute
Step-by-step explanation:
First identify what you know:
1) The pipe was flowing water for eight minutes.
2) In that eight minutes, 72 gallons of water came out.
So, if 72 gallons of water came out in eight minutes, how many gallons flowed out in a single minute? Well, assuming that the flow rate was consistent, then simply divide the total number of gallons that flowed out, by the number of minutes the pipe was open!
72/8 = 9
The pipe released 9 gallons of water per minute, thus resulting in 72 gallons of water in 8 minutes!
Hope this helps! :)
It would be 15x/9x
Hope this helps