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navik [9.2K]
4 years ago
9

What is the area of this quadrilateral need help ASAP

Mathematics
1 answer:
vova2212 [387]4 years ago
4 0

Answer:

42

Step-by-step explanation:

The figure is broken into different shapes so you find the area of each shape shown and add them up!

Step one: find the area of the triangle. 1/2*base*height* The base is 3 and the height is 4. it will be 6. This applies to the second triangle on the bottom as well. The total of both triangle is 12.

Step two: find the area of the rectangle.base*height. All you have to do is 10*3 which is 30.

Step three: now add up all the areas you got. 30+12. which is 42.

hope this helps :)

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A science classroom has 5 turtles and 7 frogs. What is the ratio of FROGS to TOTAL animals?
olasank [31]

Answer:

7:12

Step-by-step explanation:

there is 5 turtles and all 5 turtles plus 7 frogs = 12

(5+7+12)

7:12

4 0
3 years ago
Read 2 more answers
Write an equation of an ellipse in standard form with the center at the origin and a height of 12 units and width of 19 units.
gladu [14]

Answer:

The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

Step-by-step explanation:

* Lets revise the equation of the ellipse

- The standard form of the equation of an ellipse with center (0 , 0 )  

  and major axis parallel to the x-axis is x²/a² + y²/b² = 1  

# a > b  

- The length of the major axis is 2a  

- The coordinates of the vertices are ( ± a , 0 )  

- The length of the minor axis is 2b  

- The coordinates of the co-vertices are ( 0 , ± b )  

- The coordinates of the foci are ( ± c , 0 ) , where c ² = a ² − b²  

* Lets solve the problem

∵ The center of the ellipse is (0 ,0)

∵ Its width is 19 units

∴ The length of the major axis is = 19

∴ 2a = 19 ⇒ divide both sides by 2

∴ a = 19/2 ⇒ ∴ a² = 361/4

∵ Its height is 12 units

∴ The length of the minor axis is = 12

∴ 2b = 12 ⇒ divide both sides by 2

∴ b = 12/2 = 6 ⇒ ∴ b² = 36

- Lets write the equation in standard form

∵ The equation is x²/a² + y²/b² = 1

∴ x²/(361/4) + y²/36 = 1 ⇒ simplify it

∴ 4x²/361 + y²/36 = 1

* The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

7 0
4 years ago
Really need helpppp?!
user100 [1]

Answer:

6.43

pls follow me and mark brainliest ...thank u

Step-by-step explanation:

length of side x will be

Tan tita = opp/adjacent

tan65 = x/3

tan 65 is 2.14

so...you are left with 2.14=x/3

by cross multiplying

x= 2.14 × 3

= 6.43

5 0
3 years ago
What is the slope of the line shown?
earnstyle [38]

Answer:

The slope is 45.

Step-by-step explanation:

Using the slope formula by two points:

m=(y2-y1)/(x2-x1)

m=(210-120)/(4-2)

m=45

7 0
2 years ago
Read 2 more answers
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

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Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
3 years ago
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