Do distributed property
7/3+3(2/3-1/3)^2
7/3+3×(2/3-1/3)^2
7/3+3×(1/3)^2
7/3×3×1/9
7/3×1/3
7+1/3
8/3 or 2 and 2/3 or 2.66667
Answer:
The event is mutually exclusive.
Step-by-step explanation:
Mutually exclusive events are events that cannot exist simultaneously.
Thus, events that are not mutually exclusive can exist simultaneously.
Since each student only has one major, a single student cannot be both a mathematics major and a business major.
So, the event is mutually exclusive.
Add 2p² to each side of the equation. Then you have
2p² + 16p + 24 = 0 .
Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by 2 . Then you have:
p² + 8p + 12 = 0 .
Now you have a nice, comfortable, familiar-looking quadratic equation.
You can either factor the left side into (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.
That's how to solve it, and find its two solutions.
Answer:
c) 0.0156
Step-by-step explanation:
The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...
a[n] = a[1]r^(n-1)
The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...
a[n] = 8(1/2)^(n-1)
The 10th term is then ...
a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512
a[10] = 0.015625 ≈ 0.0156
Answer:
1st equation is x=11
2nd equation is ???
Step-by-step explanation:
