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masya89 [10]
2 years ago
11

A hot water heater operating at 240 V supplies to a quantity of water to warm it to the desired temperature of . What is the cos

t of the energy if the rate is $0.131/kWh?
Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

Complete Question:

A hot water heater operating at 240 V supplies 9.07 x 10⁶ joules to a quantity of water to warm it to the desired temperature of 60°C. What is the cost of the energy if the rate is $0.131/kWh?

Answer:

The cost of the energy is $0.33

Explanation:

Given;

quantity of energy supplied = 9.07 x 10⁶ joules

Converting this energy to kWh = 2.519  kWh

one unit of energy cost $0.131/kWh, then the cost 2.519 kWh will be calculated as follows;

1 kWh --------------------- $0.131/kWh

2.519 kWh ----------------- ?

= 2.519 (kWh) * $0.131/kWh

= $0.33

Therefore, if the hot water heater operating at 240 V supplies 9.07 x 10⁶ joules at the rate of $0.131/kWh, then the cost of the energy is $0.33.

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A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).
PIT_PIT [208]

The kayaker has velocity vector

<em>v</em> = (2.50 m/s) (cos(45º) <em>i</em> + sin(45º) <em>j</em> )

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and the current has velocity vector

<em>w</em> = (1.25 m/s) (cos(315º) <em>i</em> + sin(315º) <em>j</em> )

<em>w</em> ≈ (0.884 m/s) (<em>i</em> - <em>j</em> )

The kayaker's total velocity is the sum of these:

<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

That is, the kayaker has a velocity of about ||<em>v</em> + <em>w</em>|| ≈ 2.80 m/s in a direction <em>θ</em> such that

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Use pascal and pressure in the same sentence
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Identify the 4 components of an atom and what the charge is on each one ?<br><br> Please help
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Read 2 more answers
At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in
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Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

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The rate of change of this distance is calculated as;

r² = a²   +  b²

r = 101.98 km, a = 20 km, b = 100 km

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3 years ago
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